#3512. [GESP202506 五级 C++] 第 19 题
[GESP202506 五级 C++] 第 19 题
下面的C++代码实现归并排序。代码在执行时,将输出一次 HERE 字符串,因为 merge() 函数仅被调用一次。
void merge(std::vector<int>& arr, int left, int mid, int right) {
std::vector<int> temp(right - left + 1);
int i = left;
int j = mid + 1;
int k = 0;
while (i <= mid && j <= right) {
if (arr[i] <= arr[j]) {
temp[k++] = arr[i++];
} else {
temp[k++] = arr[j++];
}
}
while (i <= mid) {
temp[k++] = arr[i++];
}
while (j <= right) {
temp[k++] = arr[j++];
}
for (int p = 0; p < k; ++p) {
arr[left + p] = temp[p];
}
}
void mergeSort(std::vector<int>& arr, int left, int right) {
if (left >= right) {
return;
}
int mid = left + (right - left) / 2;
mergeSort(arr, left, mid);
mergeSort(arr, mid + 1, right);
std::cout << "HERE";
merge(arr, left, mid, right);
}
{{ select(1) }}
- 正确
- 错误